25 references to ListViewItem
Accessibility_Core_App (1)
DataBindingExample.cs (1)
103
ListViewItem item =
new
(itemName, i);
System.Windows.Forms (7)
System\Windows\Forms\Controls\ListView\ListView.ListViewItemCollection.cs (5)
94
: new
ListViewItem
(value!.ToString(), -1);
154
ListViewItem item =
new
(text, imageIndex);
206
ListViewItem item =
new
(text, imageIndex)
391
return Insert(index, new
ListViewItem
(text, imageIndex));
418
=> Insert(index, new
ListViewItem
(text, imageIndex)
System\Windows\Forms\Controls\ListView\ListViewItem.cs (2)
74
:
this
(text, ImageList.Indexer.DefaultIndex)
145
:
this
(text, imageIndex)
System.Windows.Forms.Tests (11)
SerializableTypesTests.cs (1)
163
ListViewItem listViewItem =
new
("Item1", 0)
System\Windows\Forms\AccessibleObjects\ListViewItem.ListViewItemAccessibleObjectTests.cs (1)
1624
ListViewItem listViewItem =
new
("Item 1", imageIndex: hasImage ? 0 : -1);
System\Windows\Forms\AccessibleObjects\ListViewItem.ListViewItemDetailsAccessibleObjectTests.cs (1)
151
ListViewItem listViewItem =
new
("1", 0);
System\Windows\Forms\AccessibleObjects\ListViewItem.ListViewItemImageAccessibleObjectTests.cs (2)
17
ListViewItem listViewItem =
new
("Test", 0);
42
ListViewItem listViewItem =
new
("Test", 0);
System\Windows\Forms\AccessibleObjects\ListViewItem.ListViewItemWithImageAccessibleObjectTests.cs (3)
33
ListViewItem listViewItem =
new
("Test", 0);
78
ListViewItem listViewItem =
new
("Test", 0);
115
ListViewItem listViewItem =
new
("Test", 0);
System\Windows\Forms\AccessibleObjects\ListViewLabelEditAccessibleObjectTests.cs (1)
163
ListViewItem item =
new
("Test", 0);
System\Windows\Forms\ListViewItemConverterTests.cs (1)
99
new
ListViewItem
("text", 1),
System\Windows\Forms\ListViewItemTests.cs (1)
695
ListViewItem item =
new
(text, imageIndex);
TrimTestBinaryDeserialization (1)
Form1.Designer.cs (1)
33
ListViewItem listViewItem1 = new
ListViewItem
("This is a ListViewItem with an image", 0);
WinFormsControlsTest (5)
ListViewTest.cs (2)
82
ListViewItem item1 =
new
("item1", 0)
90
ListViewItem item2 =
new
("item2", 1);
MultipleControls.cs (3)
44
ListViewItem item1 =
new
("item1", 0)
52
ListViewItem item2 =
new
("item2", 1);
56
ListViewItem item3 =
new
("item3", 0)