1 write to _openFileDialog
System.Windows.Forms.Design (1)
System\Windows\Forms\Design\FileNameEditor.cs (1)
26
_openFileDialog
= new OpenFileDialog();
5 references to _openFileDialog
System.Windows.Forms.Design (5)
System\Windows\Forms\Design\FileNameEditor.cs (5)
24
if (
_openFileDialog
is null)
27
InitializeDialog(
_openFileDialog
);
32
_openFileDialog
.FileName = stringValue;
35
if (
_openFileDialog
.ShowDialog() == DialogResult.OK)
37
return
_openFileDialog
.FileName;