1 write to _openFileDialog
System.Windows.Forms.Design (1)
System\Windows\Forms\Design\FileNameEditor.cs (1)
26_openFileDialog = new OpenFileDialog();
5 references to _openFileDialog
System.Windows.Forms.Design (5)
System\Windows\Forms\Design\FileNameEditor.cs (5)
24if (_openFileDialog is null) 27InitializeDialog(_openFileDialog); 32_openFileDialog.FileName = stringValue; 35if (_openFileDialog.ShowDialog() == DialogResult.OK) 37return _openFileDialog.FileName;