1 write to _sourceFileArg
dotnet-openapi (1)
Commands\AddURLCommand.cs (1)
24_sourceFileArg = Argument(SourceUrlArgName, "The OpenAPI file to add. This must be a URL to a remote OpenAPI file.", multipleValues: true);
4 references to _sourceFileArg
dotnet-openapi (4)
Commands\AddURLCommand.cs (4)
34ArgumentException.ThrowIfNullOrEmpty(_sourceFileArg.Value); 37var sourceFile = _sourceFileArg.Value; 52ArgumentException.ThrowIfNullOrEmpty(_sourceFileArg.Value); 54if (!IsUrl(_sourceFileArg.Value))