1 write to openFileDialog1
WinFormsControlsTest (1)
Dialogs.Designer.cs (1)
43
this.
openFileDialog1
= new System.Windows.Forms.OpenFileDialog();
4 references to openFileDialog1
WinFormsControlsTest (4)
Dialogs.cs (3)
23
TypeDescriptor.AddProvider(new AssociatedMetadataTypeTypeDescriptionProvider(
openFileDialog1
.GetType(), typeof(ExposedClientGuidMetadata)),
openFileDialog1
);
97
propertyGrid1.SelectedObject =
openFileDialog1
;
Dialogs.Designer.cs (1)
137
this.
openFileDialog1
.FileName = "openFileDialog1";