Base:
method
GetObjectData
System.Xaml.XamlException.GetObjectData(System.Runtime.Serialization.SerializationInfo, System.Runtime.Serialization.StreamingContext)
1 reference to GetObjectData
System.Xaml.Tests (1)
System\Xaml\XamlDuplicateMemberExceptionTests.cs (1)
92
Assert.Throws<ArgumentNullException>("info", () => exception.
GetObjectData
(null, new StreamingContext()));
