2 references to new
System.Windows.Forms (2)
System\Windows\Forms\Controls\ListView\ListViewItem.ListViewItemDetailsAccessibleObject.cs (1)
155
ListViewSubItem.ListViewSubItemAccessibleObject fakeAccessibleObject =
new
(owningSubItem: null, _owningItem);
System\Windows\Forms\Controls\ListView\ListViewItem.ListViewSubItem.cs (1)
64
_accessibilityObject = new
ListViewSubItemAccessibleObject
(this, _owner);