1 write to _fileDialog
System.Windows.Forms.Design (1)
System\Drawing\Design\ImageEditor.cs (1)
72
_fileDialog
= new OpenFileDialog();
4 references to _fileDialog
System.Windows.Forms.Design (4)
System\Drawing\Design\ImageEditor.cs (4)
70
if (
_fileDialog
is null)
99
_fileDialog
.Filter = filter;
105
if (
_fileDialog
.ShowDialog() == DialogResult.OK)
107
using FileStream stream = new(
_fileDialog
.FileName, FileMode.Open, FileAccess.Read, FileShare.Read);