1 write to View
System.Windows.Forms.Design.Tests (1)
System\Windows\Forms\Design\ListViewActionListTests.cs (1)
38
_actionList.
View
= View.Details;
3 references to View
System.Windows.Forms.Design (2)
System\Windows\Forms\Design\ListViewActionList.cs (2)
33
set => TypeDescriptor.GetProperties(_listView)[nameof(
View
)]!.SetValue(Component, value);
62
new DesignerActionPropertyItem(nameof(
View
),
System.Windows.Forms.Design.Tests (1)
System\Windows\Forms\Design\ListViewActionListTests.cs (1)
39
_actionList.
View
.Should().Be(View.Details);