2 references to Show
System.Windows.Forms.Design (2)
System\ComponentModel\Design\DesignerActionUI.cs (1)
390if (e.ChangeType == DesignerActionUIStateChangeType.Show)
System\ComponentModel\Design\DesignerActionUIService.cs (1)
54new DesignerActionUIStateChangeEventArgs(component, DesignerActionUIStateChangeType.Show));