1 write to ExceptionDispatchInfo
System.Text.Json (1)
System\Text\Json\Serialization\JsonSerializerOptions.Caching.cs (1)
382
ExceptionDispatchInfo
= exception;
1 reference to ExceptionDispatchInfo
System.Text.Json (1)
System\Text\Json\Serialization\JsonSerializerOptions.Caching.cs (1)
388
ExceptionDispatchInfo
?.Throw();