17 writes to PropertyName
Microsoft.CodeAnalysis.LanguageServer (17)
RunFileApiJsonSerializerContext.Error.g.cs (3)
64PropertyName = "Message", 87PropertyName = "Details", 110PropertyName = "Version",
RunFileApiJsonSerializerContext.GetProject.g.cs (2)
64PropertyName = "ArtifactsPath", 84PropertyName = "EntryPointFileFullPath",
RunFileApiJsonSerializerContext.LinePositionInternal.g.cs (2)
64PropertyName = "Line", 84PropertyName = "Character",
RunFileApiJsonSerializerContext.LinePositionSpanInternal.g.cs (2)
64PropertyName = "Start", 84PropertyName = "End",
RunFileApiJsonSerializerContext.Position.g.cs (2)
64PropertyName = "Path", 86PropertyName = "Span",
RunFileApiJsonSerializerContext.Project.g.cs (3)
64PropertyName = "Content", 87PropertyName = "Diagnostics", 108PropertyName = "Version",
RunFileApiJsonSerializerContext.RunApiOutput.g.cs (1)
64PropertyName = "Version",
RunFileApiJsonSerializerContext.SimpleDiagnostic.g.cs (2)
64PropertyName = "Location", 85PropertyName = "Message",
4 references to PropertyName
System.Text.Json (4)
System\Text\Json\Serialization\Metadata\JsonMetadataServices.cs (2)
34string? propertyName = propertyInfo.PropertyName; 37throw new ArgumentException(nameof(propertyInfo.PropertyName));
System\Text\Json\Serialization\Metadata\JsonMetadataServices.Helpers.cs (2)
177declaredPropertyName: propertyInfoValues.PropertyName, 180propertyInfo.MemberName = propertyInfoValues.PropertyName;