1 write to IndentCharacter
System.Text.Json.SourceGeneration (1)
JsonSourceGenerator.Parser.cs (1)
447
IndentCharacter
= indentCharacter,
1 reference to IndentCharacter
System.Text.Json.SourceGeneration (1)
JsonSourceGenerator.Emitter.cs (1)
1269
if (optionsSpec.
IndentCharacter
is char indentCharacter)