3 references to String100
System.ServiceModel.Primitives (3)
System\ServiceModel\ServiceModelStringsVersion1.cs (1)
611
case 100: return
String100
;
System\ServiceModel\XD.cs (2)
331
ReferenceParameters = dictionary.CreateString(ServiceModelStringsVersion1.
String100
, 100);
1065
public const string ReferenceParameters = ServiceModelStringsVersion1.
String100
;