1 reference to XmlSerializeErrorDetails
System.Private.Xml (1)
System\Xml\Serialization\XmlSerializer.cs (1)
491
throw new InvalidOperationException(SR.Format(SR.
XmlSerializeErrorDetails
, lineInfo.LineNumber.ToString(CultureInfo.InvariantCulture), lineInfo.LinePosition.ToString(CultureInfo.InvariantCulture)), e);