1 write to getTypeFromXmlName
Microsoft.Maui.Controls.Xaml (1)
XamlServiceProvider.cs (1)
207
this.
getTypeFromXmlName
= getTypeFromXmlName ?? throw new ArgumentNullException();
2 references to getTypeFromXmlName
Microsoft.Maui.Controls.Xaml (2)
XamlServiceProvider.cs (2)
227
type =
getTypeFromXmlName
(xmlType, null, currentAssembly, out exception);
241
return
getTypeFromXmlName
(xmlType, xmlLineInfo, currentAssembly, out exception);