Base:
property
IsInterface
Microsoft.CodeAnalysis.VisualBasic.Microsoft.CodeAnalysis.VisualBasic.Symbols.NamedTypeSymbol.IsInterface
13 references to IsInterface
Microsoft.CodeAnalysis.VisualBasic (13)
Symbols\BaseTypeAnalysis.vb (2)
95Debug.Assert(this.IsInterface OrElse Not base.IsInterfaceType()) 127Debug.Assert(this.IsInterface)
Symbols\Source\ImplementsHelper.vb (1)
98If container.IsInterface Then
Symbols\Source\SourceMemberContainerTypeSymbol.vb (4)
3995diag = ErrorFactory.ErrorInfo(If(IsInterface, ERRID.ERR_InterfaceInheritedTwiceWithDifferentTupleNames2, ERRID.ERR_InterfaceImplementedTwiceWithDifferentTupleNames2), 3999diag = ErrorFactory.ErrorInfo(If(IsInterface, ERRID.ERR_InterfaceInheritedTwiceWithDifferentTupleNames3, ERRID.ERR_InterfaceImplementedTwiceWithDifferentTupleNames3), 4004diag = ErrorFactory.ErrorInfo(If(IsInterface, ERRID.ERR_InterfaceInheritedTwiceWithDifferentTupleNamesReverse3, ERRID.ERR_InterfaceImplementedTwiceWithDifferentTupleNamesReverse3), 4010diag = ErrorFactory.ErrorInfo(If(IsInterface, ERRID.ERR_InterfaceInheritedTwiceWithDifferentTupleNames4, ERRID.ERR_InterfaceImplementedTwiceWithDifferentTupleNames4),
Symbols\Source\SourceMethodSymbol.vb (1)
102ElseIf container.IsInterface Then
Symbols\Source\SourceNamedTypeSymbol.vb (5)
1298If Me.IsInterface AndAlso containingSourceType IsNot Nothing AndAlso containingSourceType.IsInterface Then 1590Debug.Assert(Me.IsInterface) 2015If Not Me.IsInterface Then 2029Debug.Assert(Me.IsInterface OrElse _lazyCoClassType Is Nothing)