3 references to IsPartitionClause
Microsoft.CodeAnalysis.VisualBasic (3)
Generated\Syntax.xml.Internal.Generated.vb (2)
44294Debug.Assert(SyntaxFacts.IsPartitionClause(kind)) 56360Debug.Assert(SyntaxFacts.IsPartitionClause(kind))
Generated\Syntax.xml.Main.Generated.vb (1)
39070If Not SyntaxFacts.IsPartitionClause(kind) Then