23 references to RegionKeyword
Microsoft.CodeAnalysis.VisualBasic (23)
Generated\Syntax.xml.Internal.Generated.vb (4)
45929Debug.Assert(regionKeyword IsNot Nothing AndAlso regionKeyword.Kind = SyntaxKind.RegionKeyword) 45950Debug.Assert(regionKeyword IsNot Nothing AndAlso regionKeyword.Kind = SyntaxKind.RegionKeyword) 57995Debug.Assert(regionKeyword IsNot Nothing AndAlso regionKeyword.Kind = SyntaxKind.RegionKeyword) 58016Debug.Assert(regionKeyword IsNot Nothing AndAlso regionKeyword.Kind = SyntaxKind.RegionKeyword)
Generated\Syntax.xml.Main.Generated.vb (6)
43640Case SyntaxKind.RegionKeyword 43657Return SyntaxFactory.RegionDirectiveTrivia(SyntaxFactory.Token(SyntaxKind.HashToken), SyntaxFactory.Token(SyntaxKind.RegionKeyword), SyntaxFactory.Token(SyntaxKind.StringLiteralToken)) 43685Case SyntaxKind.RegionKeyword 43697Return SyntaxFactory.EndRegionDirectiveTrivia(SyntaxFactory.Token(SyntaxKind.HashToken), SyntaxFactory.Token(SyntaxKind.EndKeyword), SyntaxFactory.Token(SyntaxKind.RegionKeyword)) 45179SyntaxKind.RegionKeyword, 45724Case SyntaxKind.RegionKeyword
Parser\ParseConditional.vb (3)
76Case SyntaxKind.RegionKeyword 187If identifier.PossibleKeywordKind = SyntaxKind.RegionKeyword Then 256Debug.Assert(CurrentToken.Kind = SyntaxKind.IdentifierToken AndAlso DirectCast(CurrentToken, IdentifierTokenSyntax).PossibleKeywordKind = SyntaxKind.RegionKeyword,
Scanner\Directives.vb (2)
557Not IsContextualKeyword(nextNextToken, SyntaxKind.ExternalSourceKeyword, SyntaxKind.RegionKeyword)) OrElse 569Not IsContextualKeyword(nextNextToken, SyntaxKind.ExternalSourceKeyword, SyntaxKind.RegionKeyword)) Then
Scanner\KeywordTable.vb (1)
205SyntaxKind.RegionKeyword, None,
Syntax\InternalSyntax\SyntaxNodeFactories.vb (1)
347SyntaxKind.RegionKeyword,
Syntax\SyntaxKindFacts.vb (5)
67SyntaxKind.RegionKeyword, 276SyntaxKind.RegionKeyword, 358SyntaxKind.RegionKeyword, 803{"region", SyntaxKind.RegionKeyword}, 834{"region", SyntaxKind.RegionKeyword},
Syntax\SyntaxNodeFactories.vb (1)
647SyntaxKind.RegionKeyword,