2 references to RunFileApiJsonSerializerContext
Microsoft.CodeAnalysis.LanguageServer (2)
FileBasedPrograms\VirtualProjectXmlProvider.cs (2)
92
var inputJson = JsonSerializer.Serialize(input,
RunFileApiJsonSerializerContext
.Default.RunApiInput);
118
var response = JsonSerializer.Deserialize(responseJson,
RunFileApiJsonSerializerContext
.Default.RunApiOutput);