5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5384if (HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5393HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5402HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5412HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5985(newPrimaryConstructor != null || oldPrimaryConstructor != null) && HasExplicitOrSequentialLayout(newMember.ContainingType, newModel);