5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5147if (HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5156HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5165HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5175HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5748(newPrimaryConstructor != null || oldPrimaryConstructor != null) && HasExplicitOrSequentialLayout(newMember.ContainingType, newModel);