5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5147
if (
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5156
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5165
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5175
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5748
(newPrimaryConstructor != null || oldPrimaryConstructor != null) &&
HasExplicitOrSequentialLayout
(newMember.ContainingType, newModel);