5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5333if (HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5342HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5351HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5361HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5934(newPrimaryConstructor != null || oldPrimaryConstructor != null) && HasExplicitOrSequentialLayout(newMember.ContainingType, newModel);