5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5384
if (
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5393
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5402
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5412
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5985
(newPrimaryConstructor != null || oldPrimaryConstructor != null) &&
HasExplicitOrSequentialLayout
(newMember.ContainingType, newModel);