5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5389if (HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5398HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5407HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5417HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5990(newPrimaryConstructor != null || oldPrimaryConstructor != null) && HasExplicitOrSequentialLayout(newMember.ContainingType, newModel);