5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5266if (HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5275HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5284HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5294HasExplicitOrSequentialLayout(newSymbol.ContainingType, diagnosticContext.NewModel)) 5867(newPrimaryConstructor != null || oldPrimaryConstructor != null) && HasExplicitOrSequentialLayout(newMember.ContainingType, newModel);