5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5333
if (
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5342
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5351
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5361
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5934
(newPrimaryConstructor != null || oldPrimaryConstructor != null) &&
HasExplicitOrSequentialLayout
(newMember.ContainingType, newModel);