5 references to HasExplicitOrSequentialLayout
Microsoft.CodeAnalysis.Features (5)
EditAndContinue\AbstractEditAndContinueAnalyzer.cs (5)
5266
if (
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5275
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5284
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5294
HasExplicitOrSequentialLayout
(newSymbol.ContainingType, diagnosticContext.NewModel))
5867
(newPrimaryConstructor != null || oldPrimaryConstructor != null) &&
HasExplicitOrSequentialLayout
(newMember.ContainingType, newModel);