2 references to ForceConditionalAccessExpression
Microsoft.CodeAnalysis.CSharp (2)
Parser\LanguageParser.cs (2)
4283(parser.ForceConditionalAccessExpression ? LanguageParserState.ForceConditionalAccessExpression : 0); 4296_parser.ForceConditionalAccessExpression = (_previousState & LanguageParserState.ForceConditionalAccessExpression) != 0;