12 references to DotToken
Microsoft.CodeAnalysis.CSharp (6)
Binder\Binder_Expressions.cs (1)
1359return BindMemberAccessWithBoundLeft(node, this.BindLeftOfPotentialColorColorMemberAccess(node.Left, diagnostics), node.Right, node.DotToken, invoked: false, indexed: false, diagnostics: diagnostics);
Syntax.xml.Main.Generated.cs (1)
1510=> node.Update((NameSyntax?)Visit(node.Left) ?? throw new ArgumentNullException("left"), VisitToken(node.DotToken), (SimpleNameSyntax?)Visit(node.Right) ?? throw new ArgumentNullException("right"));
Syntax.xml.Syntax.Generated.cs (3)
125if (left != this.Left || dotToken != this.DotToken || right != this.Right) 135public QualifiedNameSyntax WithLeft(NameSyntax left) => Update(left, this.DotToken, this.Right); 137public QualifiedNameSyntax WithRight(SimpleNameSyntax right) => Update(this.Left, this.DotToken, right);
Syntax\SyntaxFactory.cs (1)
2304return SyntaxFactory.QualifiedName(qn.Left, qn.DotToken, SyntaxFactory.IdentifierName(gn.Identifier));
Microsoft.CodeAnalysis.CSharp.CodeStyle (1)
src\Workspaces\SharedUtilitiesAndExtensions\Compiler\CSharp\Services\SyntaxFacts\CSharpSyntaxFacts.cs (1)
1686operatorToken = qualifiedName.DotToken;
Microsoft.CodeAnalysis.CSharp.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.cs (2)
11122Assert.Equal(SyntaxKind.DotToken, node.DotToken.Kind()); 11124var newNode = node.WithLeft(node.Left).WithDotToken(node.DotToken).WithRight(node.Right);
Microsoft.CodeAnalysis.CSharp.Workspaces (2)
Simplification\Simplifiers\ExpressionSimplifier.cs (1)
303replacementNode = qualifiedName.Update((NameSyntax)newLeft, qualifiedName.DotToken, qualifiedName.Right)
src\Workspaces\SharedUtilitiesAndExtensions\Compiler\CSharp\Services\SyntaxFacts\CSharpSyntaxFacts.cs (1)
1686operatorToken = qualifiedName.DotToken;
Roslyn.Diagnostics.CSharp.Analyzers (1)
src\Workspaces\SharedUtilitiesAndExtensions\Compiler\CSharp\Services\SyntaxFacts\CSharpSyntaxFacts.cs (1)
1686operatorToken = qualifiedName.DotToken;