|
// Licensed to the .NET Foundation under one or more agreements.
// The .NET Foundation licenses this file to you under the MIT license.
using Aspire.Hosting.ApplicationModel;
using Microsoft.Extensions.DependencyInjection;
namespace Aspire.Hosting.Ats;
/// <summary>
/// ATS exports for distributed application model access.
/// </summary>
internal static class ModelExports
{
/// <summary>
/// Gets the distributed application model from the service provider.
/// </summary>
/// <param name="serviceProvider">The service provider handle.</param>
/// <returns>The distributed application model handle.</returns>
[AspireExport("getDistributedApplicationModel", Description = "Gets the distributed application model from the service provider")]
public static DistributedApplicationModel GetDistributedApplicationModel(this IServiceProvider serviceProvider)
{
ArgumentNullException.ThrowIfNull(serviceProvider);
return serviceProvider.GetRequiredService<DistributedApplicationModel>();
}
/// <summary>
/// Gets all resources in the distributed application model.
/// </summary>
/// <param name="model">The distributed application model handle.</param>
/// <returns>The resources in the model.</returns>
[AspireExport("getResources", Description = "Gets resources from the distributed application model")]
public static IResource[] GetResources(this DistributedApplicationModel model)
{
ArgumentNullException.ThrowIfNull(model);
return [.. model.Resources];
}
/// <summary>
/// Finds a resource by name.
/// </summary>
/// <param name="model">The distributed application model handle.</param>
/// <param name="name">The resource name.</param>
/// <returns>The matching resource, or <see langword="null"/> when not found.</returns>
[AspireExport("findResourceByName", Description = "Finds a resource by name")]
public static IResource? FindResourceByName(this DistributedApplicationModel model, string name)
{
ArgumentNullException.ThrowIfNull(model);
ArgumentException.ThrowIfNullOrWhiteSpace(name);
return model.Resources.SingleOrDefault(resource => StringComparers.ResourceName.Equals(resource.Name, name));
}
}
|