1 write to printDialog1
Accessibility_Core_App (1)
PrintingControls.Designer.cs (1)
34
this.
printDialog1
= new System.Windows.Forms.PrintDialog();
3 references to printDialog1
Accessibility_Core_App (3)
PrintingControls.cs (1)
77
if (
printDialog1
.ShowDialog() == DialogResult.OK)
PrintingControls.Designer.cs (2)
56
this.
printDialog1
.Document = this.printDocument1;
57
this.
printDialog1
.UseEXDialog = true;